Simple 12 Volt to 240 Volt Mini Inverter Using MOSFET & 2N2222 Transistor
by DIYTechStudio in Circuits > Electronics
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Simple 12 Volt to 240 Volt Mini Inverter Using MOSFET & 2N2222 Transistor
In this tutorial i will show you how to make a Simple 12 volt to 240 volt mini Inverter using MOSFET & 2N2222 Transistor
To build your own 12 volt to 240 volt mini Inverter using MOSFET & 2N2222 Transistor you can watch the video embedded in this step or continue reading.
Parts List
***Parts List***
- 2 * IRF540 MOSFET
- 2 * 470 Ohm
- 2 * 2N2222
- 2 * 4.7uF/50v
- 2 * 3.3k Ohm
- 2 * Heat Sink
- 1 * 2 & 3 Pin Terminal Block
- 1 * 1.2k Ohm
- 1 * RED Led
- 1 * Bulb Holder
- 1 * 240v to 12-0-12V 5amp Transformer
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***Purchase or Affiliate Links***
Banggood
- IRF540 Mosfet - https://goo.gl/RYauWz
- 2N2222 - https://goo.gl/eFc8zK
- 240 to 12-0-12v 5Amp Transformer - https://goo.gl/eDMmG4
- Heat Sink with Screw - https://goo.gl/gvAhgN
AliExpress
- IRF540 Mosfet - https://goo.gl/Sj7B2k
- 2N2222 - https://goo.gl/41g1C1
- Heat Sink with Screw - https://goo.gl/cGBzWb
Amazon USA & UK
- IRF540 Mosfet - http://amzn.to/2xyNDj9
- 2N2222 - http://amzn.to/2guRO9V
- Heat Sink with Screw - http://amzn.to/2zfFQc7
Amazon India
- IRF540 Mosfet - http://amzn.to/2xxdgpx
- 2N2222 - http://amzn.to/2ygeox1
- 240 to 12-0-12v 5Amp Transformer - http://amzn.to/2xyIZ9J
- Heat Sink with Screw - http://amzn.to/2wNUw0t
Note: all the purchase links provided are affiliate links
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If you wish to support my work then you can do by using my affiliate links given below, this way i get small commission for your purchases.
Bangood - https://goo.gl/ZUhRmV
AliExpress - https://goo.gl/jioyhV
Amazon USA - http://amzn.to/2u7ztbP
Amazon UK - http://amzn.to/2wu4nYP
Amazon India - http://amzn.to/2hroLHz
Circuit Diagram
Construct the circuit according to the circuit diagram.
Calculation :
Let's see the calculation
The frequency is given as
f = 1/T
or
f = 1/1.38*R*C
where : from our circuit diagram R3=R4=R & C1=C2=C
In my country the standard frequency is 50Hz
So considering that our f = 50Hz
since i have two spare electrolytic 4.7uF/50v, i have chosen C1 & C2 to be 4.7uF
Now we are left with R3 & R4 calculation
Substituting all the values that we know, we get
R = 1 / 1.38 * 50 * 4.7u
Hence R = 3083 = 3k
Considering the nearest available resistor value i have chosen 3.3k ohm
So our values are
R3=R4=3.3k Ohm
C1=C2=4.7uF
f = 50Hz
You can watch the construction & testing of the circuit in the video embedded in the first step or you can also watch it by clicking here
Thank you for reading !!!
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