SMPS Output Voltage Control Using PWM Technique Using IC TL494 Based SMPS. 12-0-12 V Ac to 220 V Ac @ 20 Watt. Frequency 63 KHZ
by rupjit81 in Circuits > Electronics
22 Views, 1 Favorites, 0 Comments
SMPS Output Voltage Control Using PWM Technique Using IC TL494 Based SMPS. 12-0-12 V Ac to 220 V Ac @ 20 Watt. Frequency 63 KHZ

Hello everyone, in this article Im going to demonstrate SMPS output voltage control using Pulse width modulation (PWM) technique. My SMPS input is 12V DC and output is 220V AC @ 63 Khz. With PWM adjustment output varies between 220V to 158 V AC.
Supplies
Bill of materials
C1 22PF
Q1 25N120
Q2 25N120
R1 100K
R2 100K
R3 100K
R4 100K
R5 10K
R6 10K
R7 330E 1W
R8 330E 1W
R9 100E
R10 100E
R11 20W LAMP
R12 1K
R13 1K
R14 10k
T1
U1 TL494
Construction
The work involves 220V AC mains line voltage available on power transformer T1 output. This can cause risk of electric shock. Hence this activity must not be performed with electricity handling awareness.
The IC TL494 input pin 3 is the feedback pin. The voltage at this pin is 0.85 V to 2.27 V DC. This voltage at pin 3 (feedback pin) controls the IGBT Q1 and Q2 gates. The PWM output finally controls the voltage fed to the transformer. Since the input to the transformer varies between 9.5 V AC to 6.5 V AC, the output voltage also varies.
Proper heatsinks are needed to dissipate the heat on IGBTs
Please follow the circuit diagram and transformer design sheet for building this project.
Data Obtained




Supply voltage = 12 V DC
Voltage on IGBT 1 and 2 drain = 9.5 V AC to 6.5 V AC (Transformer input at each center tap)
Transformer secondary voltage = 220V to 158 V AC (PWM)
Frequency = 63 KHZ
TL494 IC pin 3 = 0.851 to 2.27 V DC
Downloads
Transformer Design

Transformer Primary = 12 V @ 60 W
Transformer Secondary = 230 V
Primary no. of turns = (Primary volts X 10^10)/(4 x frequency (Hz) X Core area (sq. mm) X flux density (Gauss) )
Primary no. of turns = (12 X 10^10) / (4 X 65000 X 69 X 1500 ) = 4.45 or 5 turns
Secondary voltage = 230 X 1.414 = 325.22 V
No. of turns in secondary = (Secondary Voltage / Primary voltage) / Primary no. of turns
= (325.22 / 12) X 4.45 = 120.6 turns
Wire used = 38 SWG for both primary and secondary windings.
38 SWG wire current capacity = 0.350 A
30 W @ 12 V ==> 30 /12 = 2.5 A
No. of conductors in primary = 2.5 / 0.350 = 7.14 , say 8 conductors.
Secondary can have 1 conductor to serve this power.
Transformer design summary
Core area = 69 sq. mm
Operating frequency = 65 khz
No. of turns in primary = 5 ( 5 + 5 as it is bifilar winding, center tap required for push pull configuration. )
Secondary turns = 120 or 121
38 SWG copper wire
Primary has 8 conductors with 5 turns two windings in bifilar winding.
Secondary has 1 conductor 120 turns.
Conclusion
The work involves 220V AC mains line voltage available on power transformer T1 output. This can cause risk of electric shock. Hence this activity must not be performed with electricity handling awareness.