Potable 9v Dark Activated Light

Hey all!This is my first instructable and i am starting with a very simple one. It is a simple, easy to make potable dark activated light, powered by a 9v battery.

Components:
IC 1-----------ne555
C1------------100nf
C2------------100uf/25v
R1-------------330ohms
R2-------------10kilo ohms
R3-------------ldr
R4-------------4.7kilo ohms
D1-D6--------led  
B1--------------9v battery(and clip)
Others:
small pcb
soldering equipment
wires
rubber band

There are 2 circuit boards; the dark sensor board and the led board. Ne555 in the dark sensor functions in mono-stable mode. Once the resistance across ldr decreases when the light falling on it is blocked, the trigger pin receives a pulse and the light turns on. When there is light the resistance across ldr increases and the light is turned off, however it gets off after a few seconds till the 100uf capacitor gets discharged completely.

Carefully solder all the components and wires according to the schematic.

Connect the battery clip to the battery and turn off the lights of the room; the light should glow. If somehow it doesn't, check the wiring properly and also check if the battery is dead. Now point a lighted torch to the ldr, the light  will turn off again. 
After testing, place the two boards side to side on the two faces of the battery and put a rubber band around to keep them in place.

Now you have your small potable dark sensitive light ready. You can use them anywhere you like; for example you can put it inside your cupboard so whenever you open it the light turns on and you can see your things inside.
Feel free to comment.

THANKS!