PIR Light Switch(or Any AC Device) Without Microcontroller

This is a simple circuit for activating a relay connected to an AC (or DC for that matter) Device like a bulb,

I am going to assume you know how to use a relay and basic electrical wiring (google is your friend)

The circuit is designed for the use with 12v DC supply but can be easily converted into 5v supply design by using a 5v relay and shorting out the Vin and Vout of the voltage regulator(7805), make sure to test out the design in a breadboard before moving on to more permanent set up like a PCB

Testing

1.Breadboard

2.wires

3.Multimeter

4.Led

Final Assembly

PCB Clad/Perforated Board(This tutorial will be based on the PCB )

12v/5v Relay

Resistors (I used 1k,But make sure to keep a few standard values )

BC547 transistor

7805 voltage regulator(when using 12v supply)

Diode

Screw terminals,2 point,3 point

Female Header

PIR Sensor(Obviously)

I have attached images of the schematic and the link to the schematic and PCB board file (EAGLE )

https://github.com/Xavier-John/Pir-Switch

Test the circuit on a breadboard with 5v dc instead of 12v with an led Instead of the relay once everything is ready

U can Etch the PCB using the toner transfer method (u should check out other Instructables or google it for more info) and then solder it to the pcb and test it with 5v supply or 12 v supply (make sure to include a 7805v regulator)

Look up this link on calibrating the PIR sensor

https://learn.adafruit.com/pir-passive-infrared-pr...

After soldering and assembly get a light bulb and holder and move around in front of the sensor and see if it lights up, some calibration may be required on sensitivity and delay

And thats it

Make sure to mention any errors or improvements in the comments..

Thank you